|
[Sponsors] |
December 2, 2011, 10:41 |
buoyantBoussinesqSimpleFoam
|
#1 |
Member
Join Date: Jun 2011
Posts: 42
Rep Power: 15 |
In the tutorials of buoyantBoussinesqSimpleFoam, Laminar Prandtl number is defined as 0.9 and turbulent Prandtl number is defined as 0.7.
Why is the difference? Shouldn't laminar Prandtl number for air be something around 0.7? In Fluent, default settings for air are: Cp: 1006.43 mu: 1.79e-5 k = 0.0242 which give Pr = 0.744 |
|
December 2, 2011, 11:35 |
|
#2 |
Senior Member
Bernhard
Join Date: Sep 2009
Location: Delft
Posts: 790
Rep Power: 22 |
Does is really matter for a tutorial case?
|
|
December 8, 2011, 07:23 |
|
#3 |
Member
Join Date: Jun 2011
Posts: 42
Rep Power: 15 |
well not for the tutorial case, no.
I modified buoyantBoussinesqSimpleFOAM and added a heat source term into the equation. my TEqn: fvScalarMatrix TEqn ( fvm::div(phi, T) - fvm::Sp(fvc::div(phi), T) - fvm::laplacian(kappaEff, T) == heatSource // heatSource is Q/(Cp*rho) - in units [K/s] where Q is [W/m3] ); now I use a heatSource file in my 0/ directory and using setFields modify the internal values where I want my heat sources. However, the value of my heatSource input is Q/(Cp*rho). The value of heat capacity is defined in Prandtl number. That is why I asked. Right now I assume rho = 1.225 and Cp = 1006.43 but my temperature results are not always the same as I get in Fluent. If I define a boussinesq force - they are quite different If I turn the boussinesq force off, then temperature results are similar why would that be the case? |
|
December 9, 2011, 12:56 |
|
#4 |
Member
Join Date: Jun 2011
Posts: 42
Rep Power: 15 |
The thing is I create a simple room with a size x,y,z= 1x1x1m and put a heatSource with a value of 1 at the cells where x=[0.2,0.4], y=[0.4,0.6], z=[0.4,0.6].
There is a flow from left to right with a velocity of (0.1,0,0) at the inlet. so, the volumetric flow rate = 0.1 m3/s The temperature increase at the outlet is less than I expect. Using Q=m*c*deltaT, I expect a temperature increase of 0.08 K but I get 0.037 K (those are outlet average T - inlet average T) There must be something wrong with my heatSource input, I guess? Here is the domain and heatSource input: http://i.imgur.com/qDrBd.png Last edited by mikeP; December 9, 2011 at 13:00. Reason: I have uploaded the image showing the heat source |
|
July 27, 2013, 10:50 |
Incident Solar Radiation
|
#5 |
New Member
Alex Lee
Join Date: Sep 2012
Posts: 15
Rep Power: 14 |
Hi, I am working on a similar problem and would like to seek your help.
We are able to map the solar incident radiation (G, w/m^2) on the floor and wall of a air tight room. We are looking for way to use these radiative flux as BCs to drive the flow field inside the room. We are wondering the use of bouyantBoussinesaRadiationFoam allow the use of G as wall heat flux? Thanks for your help. Alex |
|
|
|